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Abhilasha Samiti (INST- 10595) | Online

Pithoragarh


ACT- 257881

Status:
Volunteeers:
Harshita  Dang  (45440)
Others-       ,  , 
Impact:
We did a lot of extra questions today
Report:
We learned a few more identities: (x + y + z)^2= x^2 + y^2 + z^2 + 2xy + 2yz + 2zx (x + y)^3= x^3 + y^3 + 3xy (x + y) (x - y)^3= x^3 - y^3 - 3xy (x - y) x^3 + y^3 + z^3 – 3xyz = (x + y + z)(x^2 + y^2 + z^2 – xy – yz – zx)
Date:
09/09/2021
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